Chapter - 2- EXERCISE 2.1 Basic Geometrical Ideas (NCERT Class 6th Maths Solution)
1. Write the next three natural numbers after 10999. Solution/Explanation: (1) 10,999 + 1 =11,000 (2) 11,000 + 1 =11,001 (3) 11,001 + 1 =11,002 2. Write the three whole numbers occurring just before 10001. Solution/Explanation: 10,001 – 1 =10,000 10,000 – 1 =9,999 9,999 – 1 =9,998 3. Which is the smallest whole number? Solution/Explanation: The whole number series is 0,1,2,3,4,5……. 0 is the smallest whole number. W = {0,1,2,3,4…} 1 is the smallest natural number. N = {1,2,3,4…..} 4. How many whole numbers are there between 32 and 53? Solution/Explanation: formula to find the whole nos between m & n is ( m − n ) − 1 ( m - n ) - 1 so applying the formula = ( 53 − 32 ) − 1 = ( 53 - 32 ) - 1 = 21 − 1 = 20 = 21 - 1 = 20 5. Write the successor of : (a) 2440701 (b) 100199 (c) 1099999 (d) 2345670 Solution/Explanation: successor of (a) 2440701 i s = 2440701 + 1 = 2440702 2440701 i s = 2440701 + 1 = 2440702 (b) 100199...