Chapter - 6 - EXERCISE 6.3 - Integers (NCERT Class 6th Maths Solution)
Q1. Find (a) 35 – (20) (b) 72 – (90) (c) (– 15) – (– 18) (d) (–20) – (13) (e) 23 – (– 12) (f) (–32) – (– 40) Solution/Explanation: To subtract two integers, we add the additive inverse of the integer that is being subtracted. So 2 -5 = 2+ (-5) as -5 is additive inverse of 5 Now we have already learned the addition of integers before a) 35 − (20) = 35+ (-20) Subtract 35 and 20 and put the sign of the bigger number 35, which is positive 15 b) 72 − (90) 72+(-90) Subtract 72 and 90 and put the sign of the bigger number 90, which is negative -18 c) (− 15) − (− 18) = (-15) + (18) As additive inverse of -18 is 18 Subtract 15 and 18 and put the sign of the bigger number 18, which is negative 3 d) (− 20) − (13) = (-20) + (13) Subtract 20 and 13 and put the sign of the bigger number 20, which is negative -7 e) 23 − (− 12) =23+12 Adding the numbers 23 and 12= 35 f)