Chapter - 5- EXERCISE 5.5 - Basic Geometrical Ideas (NCERT Class 6th Maths Solution)


1. Which of the following are models for perpendicular lines : 
(a) The adjacent edges of a table top. 
(b) The lines of a railway track. 
(c) The line segments forming the letter ‘L’. 
(d) The letter V


(a) The adjacent edges of a table top are perpendicular to each other.
(b) The lines of a railway track are parallel to each other.
(c) The line segments forming the letter 'L' are perpendicular to each other.
(d) The sides of letter V are inclined at some acute angle on each other.
Hence, (a) and (c) are the models for perpendicular lines.


2. Let  be the perpendicular to the line segment  . Let and  intersect in the point A. What is the measure of ∠PAY ?

Solution/Explanation:









3. There are two set-squares in your box. What are the measures of the angles that are formed at their corners? Do they have any angle measure that is common? 

Solution/Explanation:
   The set squares in our box  are                                                
                     

Let's measure their angles


so, Angle 900 is common between them. 


4. Study the diagram. The line l is perpendicular to line m 
(a) Is CE = EG?
(b) Does PE bisect CG? 
(c) Identify any two line segments for which PE is the perpendicular bisector. 
(d) Are these true? 
 (i) AC > FG 
(ii) CD = GH 
(iii) BC < EH. 
     
Solution/Explanation:


(a) CE = 5 - 3 = 2 units
     EG = 7 - 5 = 2 units    
     Therefore CE = EG.
(b) CE = EG therefore PE bisects CG.
(c) PE is the perpendicular bisector for line segments DF and BH
(d) (i) AC = 3 - 1 = 2 units
         FG = 7 - 6 = 1 unit
           Therefore AC > FG            True
    (ii) CD = 4 - 3 = 1 unit
         GH = 8 - 7 = 1 unit
          Therefore CD = GH          True    
    (iii) BC = 3 - 2 = 1 unit
          EH = 8 - 5 = 3 units
           Therefore BC < EH            True                                                                                             









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